To add images

Hi Swati

For storing the image in XML u have to follow the same approach as we use for storing the image in the database.

 

For storing the image in the xml use the following code on the click event of the button.

 

private void ButtonUpload_Click(object sender, System.EventArgs e)

{

      Int64 len=file1.PostedFile.ContentLength;

      Byte[] byt=new byte[len];

      Stream st=file1.PostedFile.InputStream;

      int n = st.Read(byt,0,(int)len);

      DataSet ds=new DataSet();

      ds.ReadXml(Server.MapPath("XMLFile1.xml"));

      DataRow dr=ds.Tables[0].NewRow();

      dr["id"]=TextBox1.Text;

      dr["data"]=Implode(byt);

      ds.Tables[0].Rows.Add(dr);

      ds.WriteXml(Server.MapPath("XMLFile1.xml"));

      bind();

}

public string Implode(Byte[] array)

{

      //StringBuilder sb = new StringBuilder();

      String data=String.Empty;

      for (int i = 0; i < array.Length; ++i)

            data+=array[i].ToString()+"#";

      return data;

}

 

For Display the image use the following code.

 

string id = Request.QueryString["id"].ToString();

DataSet ds = new DataSet();

ds.ReadXml(Server.MapPath("XMLFile1.xml"));

foreach (DataRow dr in ds.Tables[0].Rows)

{

   if (dr["id"].ToString() == id)

   {

       try

       {

            string[] str = dr["data"].ToString().Split('#');

            Byte[] byt = new byte[str.Length];

            for (Int64 i = 0; i < str.Length - 1; i++)

                byt[i] = Convert.ToByte(str[i].ToString());

            Context.Response.ContentType = "image/";

            Context.Response.BinaryWrite((byte[])byt);

            break;

       }

       catch (Exception ex) { Console.Write(ex); }

    }

}

Happy Coding!!