System.Drawing - Parameter is not valid

Shefali Lahariya

using code:

byte[] toBytes = Encoding.ASCII.GetBytes(objgroupconfereneResponse.groups[i].grpIcon.ToString());

if (toBytes != null)

{

MemoryStream ms = new MemoryStream(toBytes);

ms.Position = 0;

picboxserver.Image = Image.FromStream(ms);

}

please suggest me how to resolve it.

7 Replies

Know the answer? Post it — somebody with the same question will find it here.

Yogesh Vedpathak8y ago
var request = webRequest.Create(" " );
using (var response= request.GetResponse())
using (var stream =response.GetResponseStream ())
{
PictureBox.Image = Bitmap.FromStream(stream);
}
0
Shefali Lahariya8y ago
Hi yogesh ,

PF the code:

string img2 = "http://13.228.146.249:8080/jcr/groups/629.png;
byte[] toBytes = Encoding.ASCII.GetBytes(img2);
if (toBytes != null)
{
MemoryStream ms = new MemoryStream(toBytes);
ms.Position = 0;
picboxserver.Image = Image.FromStream(ms);
}

picboxserver is picturebox type.
0
Yogesh Vedpathak8y ago
Hi Shefali ,
I think this problem is occured due to differnt format of image like jpeg,bmp, Please can you share all function

public static byte[] ImageToByte2(Image img)
{
using (var stream = new MemoryStream())
{
img.Save(stream ,system.Drawing.Imaging.ImageFormat.png);
return stream.ToArray();
}
}

0
Shefali Lahariya8y ago
hi yogesh,

how to display image in picturebox getting this "http://13.228.72.152:8080/jcr/groups/629.png" url from server. buy i am getting "Parameter is not valid" error when we use below code.
0
Yogesh Vedpathak8y ago
First Explain What you are trying to Achieve ...? and use simple try catch block to handle exception ...
0
Shefali Lahariya8y ago
hi sagar,
i have tried this code getting same error.
0
Sagar Pandurang Kap8y ago
Try this :-

ImageConverter imageConverter = new System.Drawing.ImageConverter();
Image image = imageConverter.ConvertFrom(byteArray) as Image;
0