Split an array like below.

Pruthvi Patel

10y1kWindows Forms

arr[]={1,2,3,4,5,6,6,7,6,5,4,3,7,8,8,8,4,3,2,8....n}

split=2

sum=2

then the result array should be like this.

res[0]=47 //1+2+5+6+6+5+7+8+4+3

res[1]=53 //3+4+6+7+4+3+8+8+2+8

Please help me to do this.

9 Replies

Know the answer? Post it — somebody with the same question will find it here.

Midhun Tp10y ago
Accepted answer
Hi,
Please try below code -
int[] arr = { 1, 2, 3, 4, 5, 6, 6, 7, 6, 5, 4, 3, 7, 8, 8, 8, 4, 3, 2, 8};
int split = 2;
int sum = 2;
int[] res = new int[split];
int i = 0;
int j = 1;
for (int k = 0; k < arr.Length; k++)
{
res[i % split] = res[i % split] + arr[k];
if (k == ((j * sum) - 1))
{
j++;
i++;
}
}
foreach (var v in res)
{
Console.WriteLine(v);
}
+1
Ifour Hiren10y ago
static void Main(string[] args)
{
if (args != null)
{
int argument =Convert.ToInt32(args[0]);
int[] arr = { 1, 2, 3, 4, 5, 6, 6, 7, 6, 5, 4, 3, 7, 8, 8, 8, 4, 3, 2, 8 };
int index = 0;
int[] sumarry= new int[argument];
while (index < arr.Length)
{
for (int i = 0; i < argument; i++)
{
sumarry[i] += arr.Skip(index).Take(argument).Sum();
index += argument;
}
}
for (int i = 0; i < argument; i++)
{
Console.WriteLine(sumarry[i]);
}
}

}

above code helps you to make it working.
+1
Rajeev Punhani10y ago
HiPruthvi,
Please see the below snippet.
usingSystem;
usingSystem.Linq;
publicclassProgram
{
publicstaticvoidMain()
{
int[]arr={1,2,3,4,5,6,6,7,6,5,4,3,7,8,8,8,4,3,2,8};
intsplit=0;
Console.WriteLine("PleaseEnterTheSplit");
split=Convert.ToInt32(Console.ReadLine());
GetSum(arr,split);
}
protectedstaticvoidGetSum(int[]arr,intsplit)
{
intindex=0;
int[]sum=newint[split];
while(index
{
for(inti=0;i
{
sum[i]+=arr.Skip(index).Take(split).Sum();
index+=split;
}
}
for(inti=0;i
{
Console.WriteLine(sum[i]);
}
}
}
+1
Tharu Manickavasagar10y ago
This might help you.
int[]arr={1,2,3,1,2,4,5,6,1,7,3,2,1,1,3,4,5,2};
Split(3,arr);
private int[] Split(intsplitCount,int[]arr)
{
   int[] resultArr=newint[splitCount];
   int total=0;
   int k=0;
   int i=1;
   while(i
   {
      k=i-1;
      for(int m=1;m<=splitCount;m++)
      {
         for(int n=1;n<=splitCount;n++)
         {
            total+=arr[k];
            k++;
         }
         resultArr[m-1]+=total;
         total=0;
       }
   i+=(splitCount*splitCount);
   }
return resultArr;
}
+1
Pruthvi Patel10y ago
Thanks for reply but as you use 2 variable like sum1,sum2,temparr1,temparr2 and doing it sum is not solution.
I want that if split is 3 then there should be 3 variable sum1,sum2,sum3 and like wise.
I hope you will understand this problem and help me.
0
Pruthvi Patel10y ago
Thanks to all for reply and help.
0
Manas Mohapatra10y ago
Try like below:
int[] arr = { 1, 2, 3, 4, 5, 6, 6, 7, 6, 5, 4, 3, 7, 8, 8, 8, 4, 3, 2, 8 };

int[] tempArr =  new int[2];
int counter = arr.Length / (2 + 2); // SplitNo(2) + no of elements(2) = 4

for (int idx = 0; idx < counter; idx++ )
{
    tempArr[0] += arr[idx * 4];
    tempArr[0] += arr[(idx * 4 )+ 1];

    tempArr[1] += arr[(idx * 4) + 2];
    tempArr[1] += arr[(idx * 4) + 3];
}
+2
Rajeev Punhani10y ago
HiPruthvi,
Please have a look at the below snippet.
usingSystem;
usingSystem.Linq;
publicclassProgram
{
publicstaticvoidMain()
{
int[]arr={1,2,3,4,5,6,6,7,6,5,4,3,7,8,8,8,4,3,2,8};
intindex=0,sum1=0,sum2=0;
while(index
{
sum1+=arr.Skip(index).Take(2).Sum();
sum2+=arr.Skip(index+2).Take(2).Sum();
index+=4;
}
Console.WriteLine(sum1);
Console.WriteLine(sum2);
}
}
If the above solution is helpful then,accept the answer.
+2
Tharu Manickavasagar10y ago
You can do like this.
int[]arr={1,2,3,4,5,6,6,7,6,5,4,3,7,8,8,8,4,3,2,8};
int[]resultArr=newint[2];
intfirstTotal=0,secondTotal=0;
for(inti=1;i<arr.Length;i=i+4)
{
firstTotal+=arr[i-1]+arr[i];
if(i+2<arr.Length)
secondTotal+=arr[i+1]+arr[i+2];
}
resultArr[0]=firstTotal;
resultArr[1]=secondTotal;
+1