Sorting the data

Murali P

2y1.1kJQuery

hi,

can any one help me on below requirement:

i have 2 arrays as arra1 = [11,1A,1V,BD]

arra2 = [11,22,1A,CD]

i want to sort this and take the similar items

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vishal Yelve2y ago

Hi Murali,

Try this

var concatArraysUniqueWithSort = function (thisArray, otherArray) {
    var newArray = thisArray.concat(otherArray).sort(function (a, b) {
        return a > b ? 1 : a < b ? -1 : 0;
    });

    return newArray.filter(function (item, index) {
        return newArray.indexOf(item) === index;
    });
};

var arr1 = ['11','1A','1V','BD'];
var arr2 = ['11','22','1A','CD'];

var arrAll = concatArraysUniqueWithSort(arr1, arr2);

console.log(arrAll);

Sarthak Varshney2y ago

array1 = ["11", "1A", "1V", "BD"]
array2 = ["11", "22", "1A", "CD"]

# Sort the arrays
array1.sort()
array2.sort()

# Find the common elements
common_elements = []
i = 0
j = 0

while i < len(array1) and j < len(array2):
    if array1[i] == array2[j]:
        common_elements.append(array1[i])
        i += 1
        j += 1
    elif array1[i] < array2[j]:
        i += 1
    else:
        j += 1

print(common_elements)

Prasad Raveendran2y ago
To find the similar items between these arrays, you can use JavaScript's filter method along with the includes method. Here's the code to do that:
```
const commonItems = array1.filter(item => array2.includes(item));
```
This code will filter the elements of array1 and create a new array commonItems that contains only the elements that are also present in array2. In this example, commonItems will be ['11', '1A'], as these are the values that are present in both arrays.

If you want the result to be sorted, you can sort the commonItems array like this:
```
commonItems.sort();
```
Now, commonItems will be ['11', '1A'] in sorted order.
+1