sftp server upload file

Hari Krishna

3y979C#

FileInfo f=new FileInfo("C:\\mdu\\abcd.xml");
string uploadfile=f.FullName;
Console.WriteLine(f.Name);
Console.WriteLine("uploadfile"+uploadfile);
var client = new SftpClient(host, port, username, password);
client.Connect();
if(client.IsConnected){
Console.WriteLine("I AM CONNECTED");
}
var fileStream = new FileStream(uploadfile, FileMode.Open);
if(fileStream!=null){
Console.WriteLine("YOU ARE NOT NULL");
}
client.BufferSize = 4 * 1024;
client.UploadFile(fileStream, f.Name,null);
client.Disconnect();
client.Dispose();

3 Replies

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Tuhin Paul3y ago
The error in the code is that the UploadFile() method requires a third parameter, which is the remote path of the file to be uploaded. The code should be changed to:
```
client.UploadFile(fileStream, f.Name, uploadfile);
```
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Muhammad Imran Ansari3y ago
What is the issue you facing in the code?
0
Mohamed Azarudeen Z3y ago
Hi what is it you want to know?
This is what the code is.
1. A new FileInfo object is created with the path to the file to be uploaded.
2. The full path of the file is assigned to the uploadfile variable.
3. The SftpClient object is created with the SFTP server details.
4. The Connect method of the SftpClient object is called to establish a connection to the SFTP server.
5. If the connection is successful, the message "I AM CONNECTED" is printed to the console.
6. A FileStream object is created with the path to the file to be uploaded and the FileMode.Open parameter to open the file for reading.
7. If the FileStream object is not null, the message "YOU ARE NOT NULL" is printed to the console.
8. The buffer size of the SftpClient object is set to 4 KB.
9. The UploadFile method of the SftpClient object is called with the FileStream object, the name of the file, and a null Action delegate.
10. The Disconnect and Dispose methods of the SftpClient object are called to close the connection and free up resources.
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