Questions on System Tray MenuItem

softairhk

Hello! For the below listed coding, I want to ask three questions: 1) How add a submenu for "Show Control Form", i.e. when a mouse move over the "Show Control Form" option then will open a submenu. e.g. Submenu1, Submen2, Submenu 3 etc. 2) When to limit the "Show Control Form" won't open two times when it is opened? 3) How to add icon for the menuitem, e.g. add an icon on the left of "Show Control Form"? I got the complete coding, but this forum is not allow to upload. If anyone can tell me how to upload the coding? Thanks! private void InitializeNotifyIcon() { //setup the Icon NotifyIcon WSNotifyIcon = new NotifyIcon(); WSNotifyIcon.Icon = mDirIcon; WSNotifyIcon.Text = "System Tray Example"; WSNotifyIcon.Visible = true; //Create the MenuItem objects and add them to //the context menu of the NotifyIcon. MenuItem[] mnuItems = new MenuItem[3]; //create the menu items array mnuItems[0] = new MenuItem("Show Control Form", new EventHandler(this.ShowControlForm)); mnuItems[0].DefaultItem=true; mnuItems[1] = new MenuItem("-"); mnuItems[2] = new MenuItem("Exit", new EventHandler(this.ExitControlForm)); //add the menu items to the context menu of the NotifyIcon ContextMenu notifyIconMenu = new ContextMenu(mnuItems); WSNotifyIcon.ContextMenu=notifyIconMenu; } fm Softair

5 Replies

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Ben23y ago
Softair, If a menu item has submenus, I don't think it will support a click event, so I will give this example using one of the submenus of mnuItems[0]. The following code uses the this.Hide() and this.Show() to limit the number of instances to 1. //Create the MenuItem objects and add them to //the context menu of the NotifyIcon. MenuItem[] mnuItems = new MenuItem[3]; //create the menu items array mnuItems[0] = new MenuItem("Show Control Form"); mnuItems[0].DefaultItem=true; mnuItems[1] = new MenuItem("-"); mnuItems[2] = new MenuItem("Exit",new EventHandler(this.ExitControlForm)); //Create the submenus - any number will do MenuItem[] subMnuItems = new MenuItem[3]; subMnuItems[0] = new MenuItem("Show Normal",new EventHandler(this.ShowControlForm)); subMnuItems[1] = new MenuItem("Submenu 2"); subMnuItems[2] = new MenuItem("Submenu 3"); //add the subMnuItems to the [Show Control Form] menu (mnuItems[0]) mnuItems[0].MenuItems.AddRange(subMnuItems); //add the menu items to the context menu of the NotifyIcon ContextMenu notifyIconMenu = new ContextMenu(mnuItems); WSNotifyIcon.ContextMenu=notifyIconMenu; //add these 2 members somewhere in your code private void ShowControlForm(object sender,System.EventArgs e) { this.Show(); } private void ExitControlForm(object sender,System.EventArgs e) { this.Hide(); }
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Ben23y ago
Softair, I'm not sure that C# lets you add images to a menu (I'll check around though). In the mean time, why don't you look at this website. They have free, royalty-free downloads including a menu control that DOES have support for images. http://www.divil.co.uk/net/controls/dotnetwidgets/ Does this help?
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softairhk23y ago
Dear Agent 86, I would like to ask you a side question. For the below coding, how to check the Host format, e.g. The Host is the DNS or IP, if the user inputted www.yahoo.com or 203.20.20.203, so it is correct, but if the user inputted aaa or 123, so it will prompt to input a correct DNS or IP format. Please give me reply asap. Thanks! string sHost = txtHost.Text; sHost.Trim(); if (sHost.Length == 0 ) { MessageBox.Show("Please enter Host!","Warning",MessageBoxButtons.OK,MessageBoxIcon.Information); txtHost.Focus(); return; } fm Softair
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softairhk23y ago
Hello! Agent 86, It's work. Thanks for your help. Please help me to solve Questions 2 and 3. Thanks! fm Softair
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Ben23y ago
Softair, For your first question about the submenus, try this code anywhere after the code for creating the main context menu: //Create the submenus - any number will do MenuItem[] subMnuItems = new MenuItem[3]; subMnuItems[0] = new MenuItem("Submenu 1"); subMnuItems[1] = new MenuItem("Submenu 2"); subMnuItems[2] = new MenuItem("Submenu 3"); //add the subMnuItems to the "Show Control Form" menu (mnuItems[0]) mnuItems[0].MenuItems.AddRange(subMnuItems); //if it is just a single submenu, don't create the submenu as an array, and use this //instead: mnuItems[0].MenuItems.Add(subMnuItems); Let me know if it works.
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