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open file after find it with FileInfo

Mohamed Moumni

1 ) i read the part about (Working with FileInfo and DirectoryInfo classes) . but i don't find a function to open the specific file by comparing his name with the name on textbox ,

how can i open a file however his extension ?

if (diri_info.Name == textBox1.Text)

{

foreach (FileInfo file in files_info)

{

// open this file

listBox1.Items.Add(file.Name);

}

2) how can i get name for all files on 4 Directory on one specific Directory ?

think you !

2 Replies

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Amit Gupta9y ago
Accepted answer
Hey

A file/folder can be opened using Process class

System.Diagonostics.Process.Start(file.FullName);
+1
Manas Mohapatra9y ago
Get filename from textbox and search in your directory. If it exists then only open the document. Below code to find the file in a directory
string[] filePaths = Directory.GetFiles(@"c:\MyDir\", "*.bmp", SearchOption.AllDirectories);
if(filePaths.length > 0)
{
   // Open the document
}

// To open the document...
System.Diagnostics.Process.Start(@"C:\foo.jpg");
System.Diagnostics.Process.Start(@"C:\foo.doc");
+1