more clarification please in C programming

Accepted answer

Yes, if there were no ampersands in memory it would loop 'for ever' .

On the second point, there are number of issues but this should compile and print something sensible:

#include

void triangle (void);

int main () {

printf("Hello World\n");

triangle();

printf("n:\n");

return 0;

}

void triangle (void){

printf(" *\n");

printf(" ***\n");

printf("******\n");

}

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sami sam14y ago

so that why I got empty black screen even after putting the semi-colon.

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sami sam14y ago

And these codes as well.

#include

void triangle (void);

int main () {

print("Hello World");

}

triangle();

printf("n:\n");

void triangle (void){

printf("*\n");

printf("***\n");

printf("********\n");

}

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Vulpes14y ago

There's a missing semi-colon after char s[80] but otherwise you need to test in your while loops for a character which is actually present at least twice in your string such as 'h' or 'e' in this example.

If you don't do this, then you'll get a silly answer as the while loops keep on iterating until they find a '&' in memory.

0