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Json desirialization

Json desirialization

Rama Krishna

Rama Krishna

8y943Visual Basic .NET

Hi all,

I need one small help, I have below structure of json data I need to map to model class from response can anyone help me how

{

"data":[

{

"firstName":"",

"lastName":""

},

{

"firstName":"",

"lastName":""

}

] ,

"form":

{

"schema":[

{

"Id":101,

"Address":"Hyd"

},

{

"Id":101,

"Address":"Hyd"

}

]

}

}

4 Replies

Know the answer? Post it — somebody with the same question will find it here.

Hiten Pandya8y ago
Accepted answer
Hi Rama Krishna,

You can use JObject class of Newtonsoft.Json.Linq namespace. Which helps you to read the values using key's. Parse your string into object of JObject and then use the key like,
JObject jobject = JObject.Parse(str);//json string that you want to access for data.
string firstname = jobject["firstname"];
So, I just pass your json string into one model which has two property data and schema to show the array from json string.
//Model class
public class DemoModel
{
    public DemoModel(string json)
    {
        JObject jObject = JObject.Parse(json);
        JToken jUser = jObject["form"];
        schema = jUser["schema"].ToArray();
        jUser = jObject["data"];
        data = jUser.ToArray();
    }

    public Array schema { get; set; }

    public Array data { get; set; }
}

//Use of Model class in main  method
string jsonstr = "{\"data\":[{\"firstName\":\"ABC\",\"lastName\":\"DEF\"},{\"firstName\":\"XYZ\",\"lastName\":\"PQR\"}],\"form\":{\"schema\":[{\"Id\":101,\"Address\":\"Hyd\"},{\"Id\":102,\"Address\":\"Pune\"}]}}";

DemoModel dm = new DemoModel(jsonstr);

foreach (var d in dm.schema)
{
    schema += d;
}
lblSchema.Text = schema;

foreach (var d in dm.data)
{
    strdata += d;
}
lblData.Text = strdata;
Output will be like,
Hope it hepls you.

Thanks.
0
Hiten Pandya8y ago
Hi Rama,

Glad that it helps you and thanks for accepting the answer. Yes, you are right I have to use jUser[0]["schema"] instead of jUser["schema"].

Thanks for the correction.
0
Rama Krishna8y ago
Hi Hiten,

Thank you for your reply and solution. It's working fine but one small correction
Instead jUser["schema"] need to use below statement.
jUser[0]["schema"]

Once again thank you.
0
Chandan Prasad8y ago
please go through the below link and see if it helps.

https://stackoverflow.com/questions/25052293/deserialize-json-to-c-sharp-classes
0