hi friends this is my code....
select distinct convert(varchar,date,103)as date,convert(datetime,date,103)as date1 from [sample] order by date desc;
if i m using this...
i m getting two columns.....like this...
date1 date
05-12-2013 2013-12-05 00:00:00.000
20-08-2013 2013-08-20 00:00:00.000
09-07-2013 2013-07-09 00:00:00.000
07-06-2013 2013-06-07 00:00:00.000
04-05-2013 2013-05-04 00:00:00.000
07-03-2013 2013-03-07 00:00:00.000
18-02-2013 2013-02-18 00:00:00.000
10-01-2013 2013-01-10 00:00:00.000
this is my problem...i want to display date1 column only without changing order....how do i get that date column....help me as soon as possible....
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selva kumarPosted May 29, 2013, 7:25 AM
this is my exact query...
select date1 from (select distinct convert(varchar,convert(datetime,date,105),103) as date1,convert(datetime,date,103)as date2 from [sample]) g order by convert(datetime,convert(varchar,date1,2),103) desc;
Shankar MPosted May 22, 2013, 5:32 AM
You can use this,
SELECT CONVERT(VARCHAR,GETDATE(),105)
Thanks, Shankar M
selva kumarPosted May 18, 2013, 6:09 AM
Tejas PatelPosted May 18, 2013, 5:12 AM
Example : string.Format("{0:dd/MM/yyyy}", datalist1.Rows[0]["date"])