How to manage menu in xml

  Your answer is not clear. please explain or give any example.

 

  what is your xml  format, "_Menu" Partial view not available.

Create menu model...

 

public class menu
{
public List Module { get; set; }

}
public class Module
{
public string name { get; set; }
public List

form { get; set; }
}

public class Form
{
public string name {get;set;}
public string link { get; set; }
public bool access { get; set; }
public List form1 { get; set; }
}
public class Form1
{
public string name{get;set;}
public string link { get; set; }
public bool access { get; set; }

}

 

 

 

 Create menu Action ...

 

 

public ActionResult menu()
{
XmlDocument doc = new XmlDocument();
int id = Convert.ToInt32(User.Identity.Name);
string path = Server.MapPath("~/XMLFiles/xxxx.xml");
doc.Load(path);
menu me = new menu();
me.Module = new List();

XmlNodeList xnList = doc.SelectNodes("/Modules/Module");
// List lststr = new List();
foreach (XmlNode xn in xnList)
{
Module md = new Module();
md.name = xn.Attributes["name"].InnerText;
md.form = new List();
XmlNodeList nodes = xn.ChildNodes;
foreach (XmlNode node in nodes)
{
string access;
Form formo = new Form();
formo.form1 = new List();
XmlNodeList formnodes = node.ChildNodes;
if (formnodes.Count > 0)
{
foreach (XmlNode formnode in formnodes)
{
Form1 formn = new Form1();

access = formnode.Attributes["access"].InnerText;
if (access == "true" || access == "True")
{

formn.name = formnode.Attributes["name"].InnerText;
formn.link = formnode.Attributes["link"].InnerText;
formo.form1.Add(formn);

}
}
}
access=node.Attributes["access"].InnerText;
if ( access== "true" || access=="True")
{

formo.name = node.Attributes["name"].InnerText;
formo.link = node.Attributes["link"].InnerText;

md.form.Add(formo);
}

//string lastName = xn["LastName"].InnerText;
}
me.Module.Add(md);
}

return PartialView("_Menu", me);
}

 

 

 

 Create menu particle view.....

 

@model xxxxxx.Data.Models.menu