Hex To Integer Converter

This is my code I want to use to convert a two character hex code e.g FF into an integer e.g 255. But there is just one problem I want to use just one char* in the arguments e.g "FF". This is because my other program grabs values from an ini file just like this and it is getting incredibly difficult. Anyone with help would be greatly greatly appreciated. converthex2dec("F","F"); int converthex2dec(char* one,char* one) { int returnval; int Temp; Temp=atoi(one); if (one == "1" || "2" || "3" || "5" || "6" || "7" || "8" || "9") returnval = 16 * Temp; if (one == "A") returnval=160; if (one == "B") returnval=176; if (one == "C") returnval=192; if (one == "D") returnval=208; if (one == "E") returnval=224; if (one == "F") returnval=240; if (two == "1" || "2" || "3" || "4" || "5" || "6" || "7" || "8" || "9") returnval = returnval + atoi(two); if (two == "A") returnval = returnval + 10; if (two == "B") returnval = returnval + 11; if (two == "C") returnval = returnval + 12; if (two == "D") returnval = returnval + 13; if (two == "E") returnval = returnval + 14; if (two == "F") returnval = returnval + 15; return returnval; } --ZogoChieftan

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robin 022y ago
converthex2dec("FF"); first variant: int converthex2dec(char* cr_value) { int returnval = 0; if (cr_value[0] == '1' || '2' || '3' || '5' || '6' || '7' || '8' || '9') returnval = 16 * atoi(cr_value[0]); if (cr_value[0] == "A") returnval=160; else if (cr_value[0] == "B") returnval=176; ....... if (cr_value[1] == '1' || '2' || '3' || '4' || '5' || '6' || '7' || '8' || '9') returnval = returnval + atoi(cr_value[1]); ........ return returnval; } second variant: int converthex2dec(char* cr_value) { int return_value = 0; for (int i = 0; i < strlen(cr_value); i ++) { return_value = return_value*16 + converthex2dec(cr_value[i]); } } int converthex2dec(char in_val) { //as in first variant }
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