Error While Integrating API ?

Hi friends,

When I am trying to push xml to webapi with basic authorization. the following error occured.

"The underlying connection was closed: An unexpected error occurred on a send."

Code

string URL = "www.abc.com";
string xml_RN ="Some Xml File" ;
//Create a HttpWebRequest object
HttpWebRequest req_RN = (HttpWebRequest)WebRequest.Create(URL);
byte[] AuthBytes = Encoding.ASCII.GetBytes(UserName + ":" + Password);
string sAuth = Convert.ToBase64String(AuthBytes);
req_RN.Headers.Add("Authorization", "Basic" + sAuth);
//Set the Credentials property
NetworkCredential cred = new NetworkCredential(UserName, Password);
req_RN.Credentials = cred;
req_RN.PreAuthenticate = true;
//Security Protocol
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls | SecurityProtocolType.Tls11 | SecurityProtocolType.Tls12 | SecurityProtocolType.Ssl3;
ServicePointManager.Expect100Continue = true;
//Convert xml string to a byte array
byte[] postDataBytes = Encoding.ASCII.GetBytes(xml_RN);
//Set the Method property
req_RN.Method = "POST";
//Set the ContentType property of the "HttpWebRequest"
req_RN.ContentType = "application/xml";
req_RN.Accept = "application/xml";
//Set the ContentLength property of the "HttpWebRequest"
req_RN.ContentLength = postDataBytes.Length;
Stream requestStream = req_RN.GetRequestStream();
requestStream.Write(postDataBytes, 0, postDataBytes.Length);
requestStream.Close();

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Aakash Maurya7y ago
At this post there are many options given for the resolution

https://stackoverflow.com/questions/32788409/c-sharp-httpwebrequest-the-underlying-connection-was-closed-an-unexpected-error/32789483
0
Ajit More7y ago
Try your solution.

But still same error occured
0
Aakash Maurya7y ago
I was facing the same problem.

Adding following line worked for me.
if (ServicePointManager.SecurityProtocol.HasFlag(SecurityProtocolType.Tls12) == false)
{
ServicePointManager.SecurityProtocol = SecurityProtocolType.Ssl3 | SecurityProtocolType.Tls | SecurityProtocolType.Tls11 | SecurityProtocolType.Tls12;
}
Replace the SecurityProtocol line with mine one and try to give a shot.
0