Error: 2nd time enter login page will Success.

Hi. My name is Rupesh.

Actully, i am creating login page with help of angularjs and webmethod.

problem is, first enter login details not connect .

but, second time same details enter will connected.

so, please any one tell me where is the problem.

it's very urgent guys. my job issue. please tell me anyone.

Thank you.

Angularjs:

"text/javascript" src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.9/angular.min.js">
var app = angular.module('myApp', []);
app.controller('myController', function ($http, $scope, $window) {
$scope.savedata = function () {
debugger
var post = $http({
method: "post",
url: "login.aspx/insertpassword",
dataType: 'json',
data: { Username: $scope.username, Password: $scope.password },
headers: { "ContentType": "application/json" }
});
post.success(function (data, status) {
$window.alert(data.d);
if (data.d == 'ok')
{
window.location = 'http://localhost:12035/user/dashboard.aspx';
}
else
{
$window.alert(data.d);
}
});
post.error(function (data, status) {
$window.alert(data.d);
});
}
});

Html code:

<body ng-app="myApp" ng-controller="myController">
<div class="form-group">
<label class="form-label">Email addresslabel>
<input type="email" class="form-control" id="exampleInputEmail1" ng-model="username" aria-describedby="emailHelp" placeholder="Enter email" />
div>
<div class="form-group">
<label class="form-label">
Password
<a href="./forgot-password.html" class="float-right small">I forgot passworda>
label>
<input type="password" class="form-control" id="exampleInputPassword1" ng-model="password" placeholder="Password" />
div>
<div class="form-footer">
<button type="submit" class="btn btn-primary btn-block" ng-click="savedata()">Sign inbutton>
div>
body>

Webmethod:

public static string insertpassword(string Username,string Password)
{
using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["dbconnect"].ConnectionString))
{
SqlCommand cmd = new SqlCommand("Logincheck", con);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@UserName", Username);
cmd.Parameters.AddWithValue("@Password", Password);
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataSet ds = new DataSet();
da.Fill(ds);
if (Convert.ToInt32(ds.Tables[0].Rows[0][0].ToString())>0)
{
HttpContext.Current.Session["UserID"] = Username;
return "ok";
}
else
{
// error.Visible = true;
return "UserName or Password Invalid";
}
}
}

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vincent Maverick Durano8y ago
So what's really is your issue? Can you please explain furthermore?

I understand that your code will process but do you think the process is correct? I'm pointing out the If-statement so that you would be able to trace it. What's the value of ds.Tables[0].Rows[0][0].ToString()? does the code goes into the line HttpContext.Current.Session["UserID"] = Username; if the statement is true?
0
Rupesh N8y ago
i already try debugger but, their is no problem that, same process will repeate.means, first login process and second time also same process.

and

what's problem in if statement?
plz, tell me
0
Vincent Maverick Durano8y ago
Use the debugger, step into your codes to figure out what's going on. Your issue is probably at your If-statement.
0