Count lines and numbers in textbox input string values

@Muhammad Imran Ansari,

Thanks for code.in this code count numbers work ok.but count lines not work correct.if we use bracket with then its not caluclated lines.

Textbox1
1.2.3.
4.5.6.
[1.2.
3.4]5.
1.2.3.4.

5 = lines
 30 = numbers
Here 5 lines is wrong.
it should be after close bracket number is 5
so 5 x 2 lines = 10. + remain without using bracket 
lines 3
so taltal lines should be 13 is correct answer.

so look in to this and share revised pls.

Hi Luv L,

You can try the below code for your problem statement.

private void RsButton7_Click_1(object sender, EventArgs e)
{
    int countLines = 0;
    int countNumbers = 0;
    bool insideBrackets = false;
    int bracketNumbersCount = 0;
    int multiplier = 1;

    foreach (string line in txtDraft.Lines)
    {
        // Skip blank lines or lines with only whitespace
        if (string.IsNullOrWhiteSpace(line)) continue;

        if (line.Contains("["))
        {
            insideBrackets = true;
            bracketNumbersCount = 1;  // Start counting numbers inside brackets
        }

        if (insideBrackets)
        {
            // Count numbers inside the brackets
            string content = line;

            if (line.Contains("]"))
            {
                // End of bracketed section
                insideBrackets = false;
                content = content.Substring(0, content.IndexOf(']')).Trim();

                // Extract multiplier if it exists after the bracket
                string remainingText = line.Substring(line.IndexOf(']') + 1).Trim();
                if (int.TryParse(remainingText.Split('.')[0], out int result))
                {
                    multiplier = result;
                }
                else
                {
                    multiplier = 1;  // Default multiplier if not specified
                }
            }

            // Split and count numbers within this part of the bracketed content
            string[] items = content.Split('.');
            foreach (string item in items)
            {
                if (int.TryParse(item.Trim(), out _))
                {
                    bracketNumbersCount++;
                }
            }

            // If we're at the end of the brackets, apply the multiplier
            if (!insideBrackets)
            {
                countNumbers += bracketNumbersCount * multiplier;
                multiplier = 1;  // Reset multiplier for next section
            }
        }
        else
        {
            // Count numbers outside of brackets normally
            string[] items = line.Split('.');
            foreach (string item in items)
            {
                if (int.TryParse(item.Trim(), out _))
                {
                    countNumbers++;
                }
            }
        }

        countLines++;
    }

    rsLabel1.Text = $"{countLines} = lines - {countNumbers} = numbers";
}

Thank you.!

Kindly anybody solve this.

Dear @Local Coders,

Thanks for your reply.i have already done result same as above code for task-1 like above mentioned.

if i want to start "[" open and "]"close bracket with multiply tnumbers like 10 (multiply number  may be any number) used like above task2.then result will come as per above code.if i want to change the input in textbox using bracket with timing what is the impliment of code.

i hope ypu understand my logic.

Thanks.

private void textBox1_TextChanged(object sender, EventArgs e)
{
    // Count lines
    int lineCount = textBox1.Lines.Length;
    labelLineCount.Text = "Lines: " + lineCount;

    // Count numbers
    int numberCount = CountNumbers(textBox1.Text);
    labelNumberCount.Text = "Numbers: " + numberCount;
}

private int CountNumbers(string text)
{
    int numberCount = 0;
    string[] words = text.Split(new char[] { ' ', '\n', '\r', '\t' }, StringSplitOptions.RemoveEmptyEntries);

    foreach (string word in words)
    {
        if (int.TryParse(word, out _)) // Checks if the word is a number
        {
            numberCount++;
        }
    }

    return numberCount;
}