alphabet and number counts using method count()

public static void Main()
{
string test = Console.ReadLine();
int lettercount;
int digitcount;
count(test.ToCharArray(),out digitcount,out lettercount);
Console.WriteLine("digit count : " + digitcount.ToString());
Console.WriteLine("letter count : " + lettercount.ToString());

Console.ReadKey();
}
private static void count(char[] p,out int digitcount, out int lettercount)
{
digitcount = 0;
lettercount = 0;
for (int i = 0; i < p.Length; i++)
{
if (char.IsDigit(p[i]))
{
digitcount++;
}
if (char.IsLetter(p[i]))
{
lettercount++;
}
}

ok

 

please complete the whole Main() and count() method  

and using out keyword instead of return or ref

 

i can`t execute it 

you can use these methods to find out if  character is a digit or a letter in your count method: 

 

char.IsDigit(args[i]), char.IsLetter(args[i])

 

here is another way :

 

string test = "gpdw235mw3s393"

Console.WriteLine(test.Count(char.IsDigit));  //gives number of digits...

Console.WriteLine(test.Count(char.IsLetter)); //gives number of letters