Add extra bracktes.

Ankush Verma

4y1kLearn iOS Programming

Hello everyone I have parse static string using this JObject.Parse(data) but it's add extra brackets .

9 Replies

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Rohan4y ago
Muhammad Imran Ansari I have used this dynamic json = JObject.Parse(data).ToString();
It's again convert this string.
+2
Rohan4y ago
Please any help me. Very argent this for me
+2
Rohan4y ago
okay let me check this bro
+2
Muhammad Imran Ansari4y ago
You can also do this without Regex. like:
string data2 = json.Replace("\r\n", "");
string finaldata = data2.Replace("\"", "");
An other way to deserialize your object is write a class and use JsonConvert calls to deserializeobject. like:
public class Root
{
    public List attendee { get; set; }
}
public class Attendee
{
    public string attendeeEmail { get; set; }
    public string attendeeName { get; set; }
    public string attendeePhone { get; set; }
}

var data = "{\"attendee\":[{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}";
var finalData = JsonConvert.DeserializeObject(data);
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Rohan4y ago
RuntimeBinderException: The best overloaded method match for 'System.Text.RegularExpressions.Regex.Replace(string, string, string)' has some invalid arguments

This error showing
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Muhammad Imran Ansari4y ago
You can remove \r\n with following code:
string data2 = Regex.Replace(json, "\r\n", "");
string finaldata = Regex.Replace(data2, "\"", "");
+3
Rohan4y ago
I have faced this same problem and I have use .tostring it's add extra code
"{\r\n \"publResult\": [\r\n {\r\n \"key\": {\r\n \"Term\": \"flower\"\r\n },\r\n \"data\": [\r\n {\r\n \"PublImgUrl\": \"https://picsum.photos/200/300.jpg\",\r\n \"Name\": \"Jhon\",\r\n \"Title\": \"owershop\",\r\n \"Description\": \"Online\"\r\n },\r\n {\r\n \"PublImgUrl\": \"https://picsum.photos/200/300.jpg\",\r\n \"Name\": \"JhonCena\",\r\n \"Title\": \"weddings\",\r\n \"Description\": \"FLOWERS\"\r\n }\r\n ]\r\n },\r\n {\r\n \"key\": {\r\n \"Term\": \"Pizza\"\r\n },\r\n \"data\": [\r\n {\r\n \"PublImgUrl\": \"https://picsum.photos/200/300.jpg\",\r\n \"Name\": \"Harry\",\r\n \"Title\": \"benny\",\r\n \"Description\": \"TAMELAC\"\r\n },\r\n {\r\n \"PublImgUrl\": \"https://picsum.photos/200/300.jpg\",\r\n \"Name\": \"Roma\",\r\n \"Title\": \"benny\",\r\n \"Description\": \"Michelle\"\r\n }\r\n ]\r\n }\r\n ]\r\n}"
+2
Muhammad Imran Ansari4y ago
You cant remove the doubly braces as thats how json is represented in a JObject and its default behaviour. You can use Jobject().Tostring() like:
var data = "{\"attendee\":[{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}";
dynamic json = JObject.Parse(data).ToString();
Output:
{
  "attendee": [
    {
      "attendeeEmail": "[email protected]",
      "attendeeName": "Token",
      "attendeePhone": "12345678"
    },
    {
      "attendeeEmail": "[email protected]",
      "attendeeName": "Arnab",
      "attendeePhone": "6483652"
    }
  ]
}
+3
Ankush Verma4y ago
This is my code

var data = "{\"attendee\":[{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}";
dynamic json = JObject.Parse(data);

After parse this data .
"{{\"attendee\":[{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Token\",\"attendeePhone\":\"12345678\"},{\"attendeeEmail\":\"[email protected]\",\"attendeeName\":\"Arnab\",\"attendeePhone\":\"6483652\"}]}}"; Add extra brackets
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